Unterminated string literal python ошибка

Решил запустить скрипт сделал все по инструкции и тут выскакивает такое. Не подскажите как это исправить друзья программисты буду очень благодарен(
Ошибка

C:\Users\Наталья\AppData\Local\Programs\Python\Python311\python.exe C:\Users\Наталья\PycharmProjects\pythonProject1\main.py 
  File "C:\Users\Наталья\PycharmProjects\pythonProject1\main.py", line 35
    unq_filter_params =["colorbalance=rs=.3","colorbalance=gs=-
                                             ^
SyntaxError: unterminated string literal (detected at line 35)

Process finished with exit code 1

Сам код

import moviepy
from moviepy.editor import *
import random
from pathlib import Path
import string

def create_file_list(folder):
    return [str(f) for f in Path(folder).iterdir()]

def create_image_list(folder):
    image_list=[]
    folder = Path(folder)
    if folder.is_file():
        image = ImageClip(str(folder),duration=1)
        image_list.append(image)
    if folder.is_dir():
        for file in sorted(folder.iterdir(), reverse=True):
            image = ImageClip(str(file),duration=1)
            image_list.append(image)
    return image_list

def filename(folder):
    file_name = ''.join(random.choice(string.ascii_lowercase)
for i in range(5))
    file_name = str(Path(folder).joinpath(file_name + '.mp4'))
    return file_name

#Папка для сохранения видео
result_folder = r'C:\Users\Наталья\Desktop\SAVE'
#Папка с картиками
images = create_image_list(r'C:\Users\Наталья\Desktop\PNG')
#Папка с видео которые будут обработаны
video_ls = create_file_list(r'C:\Users\Наталья\Desktop\VIDEO')
#Фильтрыpip
unq_filter_params =["colorbalance=rs=.3","colorbalance=gs=-
0.20","colorbalance=gs=0.20","colorbalance=bs=-
0.30","colorbalance=bs=0.30","colorbalance=rm=0.30","colorbalanc
e=rm=-0.30","colorbalance=gm=-0.25","colorbalance=bm=-
0.25","colorbalance=rh=-0.15","colorbalance=gh=-
0.20","colorbalance=bh=-0.20"]

Скриншот фрагмента кода удален модератором.

We can’t deny that errors are inevitable, and one of them is the syntaxerror: unterminated string literal.

Whether you’re new to coding or even a pro developer, it’s important to understand this error so you can troubleshoot it and bug-free programs.

If you are struggling to fix this error, this article is indeed for you.

In this article, we will explore how to fix the unterminated string literal, a SyntaxError in Python and JavaScript.

The syntaxerror: unterminated string literal occurs when there is an unterminated string literal somewhere in your code. String literals should be enclosed by single (‘) or double (“) quotes.

Here’s an example of code that would cause a SyntaxError, specifically an unterminated string literal, in both Python and JavaScript

Python:

sample_string = "Hi, welcome to Itsourcecode, this a sample of an unterminated string

JavaScript:

let sampleString = "Hi, welcome to Itsourcecode, this a sample of an unterminated string;

As you have noticed in both examples, the string is not properly enclosed by quotes. The closing quote is missing, as a result, it will throw a SyntaxError.

Why does “unterminated string literal” SyntaxError occur?

The syntaxerror: unterminated string literal occurs when you forget to put a closing quotation mark at the end of a string in Python or JavaScript.

It can also happen when you have escaped your string literal incorrectly or if your string literal is split across multiple lines.

Here are the common causes of why this error keeps on bothering you:

👉 One common reason for this error is when the opening and closing quotation marks do not match.

👉 Forgetting to close the string with the correct quotation mark on any line can also trigger this error.

👉 Having special characters within a string, like unescaped quotation marks or newline characters, can interfere with properly ending a string literal.

How to fix the “syntaxerror: unterminated string literal”?

To fix the syntaxerror: unterminated string literal, check if you have to open and close quotes for your string literal, ensure that you have properly escaped your string literal correctly, and avoid splitting your string literal across multiple lines.

Here are the following solutions that can help you to resolve the error.

Solution 1: Add the missing quotation mark

Adding the missing quotation mark fixes the error right away.

For example in Python:

sample_string = "Hi, welcome to Itsourcecode, this a sample of an unterminated string" ✅
print(sample_string)

Output:

Hi, welcome to Itsourcecode, this a sample of an unterminated string

For example in JavaScript:

let sampleString = "Hi, welcome to Itsourcecode, this a sample of an unterminated string";✅

console.log(sampleString);

Output:

Hi, welcome to Itsourcecode, this a sample of an unterminated string

Solution 2: Split the string across multiple lines using the + operator

If you want to split a string across multiple lines, you can use the + operator to concatenate multiple strings.

For example in Python:

sample_string = ("Hi " ✅
             "welcome to Itsourcecode"
             " this a sample of an unterminated string")
print(sample_string)

Output:

Hi welcome to Itsourcecode this a sample of an unterminated string

For example in JavaScript:

let sampleString = ("Hi, " ✅
                +"welcome to Itsourcecode " 
                + "this a sample of an unterminated string");
console.log(sampleString);

Output:

Hi, welcome to Itsourcecode this a sample of an unterminated string

Solution 3: Use backslashcharacter or escape quotes within the string

If you want to include a quote character within a string, you need to escape it using a backslash (\).

For example in Python:

sample_string = ("Hi welcome to \"Itsourcecode\" this a sample of an unterminated string")✅
print(sample_string)

Output:

Hi welcome to "Itsourcecode" this a sample of an unterminated string

For example in JavaScript:

let sampleString = ("Hi welcome to \"Itsourcecode\" this a sample of an unterminated string")✅
console.log(sampleString);

Output:

Hi welcome to "Itsourcecode" this a sample of an unterminated string

Solution 4: Use the correct type of quotes

Ensure that you are using the correct type of quotes for your string literals. If you start a string with a single quote (‘), you need to end it with a single quote.

If you start a string with a double quote (“), you need to end it with a double quote.

For example in Python:

sample_string = ('Hi welcome to "Itsourcecode" this a sample of an unterminated string')✅
print(sample_string)

For example in JavaScript:

let sampleString = ('Hi welcome to "Itsourcecode" this a sample of an unterminated string')✅
console.log(sampleString);

Solution 5: Split the string across multiple lines using template literals (JavaScript only)

You can use template literals in JavaScript to split a string across multiple lines.

For example:

let sampleString = `Hi ✅
welcome to Itsourcecode 
this a sample of an unterminated string`;
console.log(sampleString);

Output:

Hi 
welcome to Itsourcecode 
this a sample of an unterminated string

Conclusion

In conclusion, the error message syntaxerror: unterminated string literal occurs when there is an unterminated string literal somewhere in your code. String literals should be enclosed by single (‘) or double (“) quotes.

To fix this error, you have to check if you have to open and close quotes for your string literal, ensure that you have properly escaped your string literal correctly, and avoid splitting your string literal across multiple lines.

This article already discussed what this error is all about and multiple ways to resolve this error.

By executing the solutions above, you can master this SyntaxError with the help of this guide.

You could also check out other SyntaxError articles that may help you in the future if you encounter them.

• Syntaxerror unexpected reserved word await
• Uncaught syntaxerror expected expression got
• Syntaxerror await is only valid in async function

We are hoping that this article helps you fix the error. Thank you for reading itsourcecoders 😊

Currently, you cannot nest quotes inside an f-string, even inside a replacement field. The " in the first argument to replace is terminating the f-string literal, meaning the " that you want to terminate the string is actually starting a new string literal.

For now, use f"""...""" to define the literal.

This restriction has been lifted as of (at least) Python
3.12.0.b1 , due to the formalization of f-string literals in the grammar by PEP 701:

Python 3.12.0b1 (main, Jun  4 2023, 16:00:02) [Clang 11.1.0 ] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> string = str
>>> value = 9
>>> f"'{string(value).replace('"', '""')}'"
"'9'"

Python 3.12 just recently entered beta; 3.12.0b2 is currently available. The final release is expected in October 2023.