Сообщение ошибки unknown system variable a

monah1983

0 / 0 / 1

Регистрация: 29.08.2013

Сообщений: 70

1

25.06.2017, 19:24. Показов 1492. Ответов 8

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Пишу авторизацию для сайта.
Пишет ошибку

Errormessage: Unknown system variable ‘a’
Warning: mysqli::query(): Couldn’t fetch mysqli in G:\OpenServer\domains\localhost\test1\session.php on line 12

Fatal error: Call to a member function fetch_assoc() on null in G:\OpenServer\domains\localhost\test1\session.php on line 14

код session.php

PHP
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<?php
session_start();
 
 
 if (isset($_SESSION ['name'])) {
     unset($_SESSION['name']);
 }
if(isset($_POST['user']) and isset($_POST['pass'])) {
        $username = htmlspecialchars(trim($_POST['user']));
        $password = md5(htmlspecialchars(trim($_POST['pass'])));
        include ('db.php');
        $query = $db->query("SELECT 'username', 'password' FROM 'users' WHERE 'username' = '$username' AND password = '$password'");
 
        $result = $query->fetch_assoc();
        if ($result) {
            $_SESSION['name'] = $username;
        } else echo "Не правильные данные при входе";
}
 
if(isset($_SESSION['name'])) {  
        echo "Hello " . $_SESSION['name'];
        echo "<br><a href =\"?exeit\"> EXIT </a>";
}
 
 
 
if (isset($_GET['exeit'])){
    unset($_SESSION['name']);
    header('location: ../index.php');
}
 
 
if (!isset($_SESSION['name'])) {
    echo '
        <form method="post" action="">
        <input type="text" name="user" placeholder="Name"> <br>
        <input type="password" name="pass" placeholder="Пароль"> <br>
        <input type="submit" name="submit-login" value="Login">
        </form>
        <a href="https://www.cyberforum.ru/reg.php">Регистрация</a>
        
        ';
    }
?>

код db.php

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<?php
$db = new mysqli('localhost', 'root', '', 'test');
 
if (!$db->query("SET a=1")) {
    printf("Errormessage: %s\n", $db->error);
}
 
/* close connection */
$db->close();
?>

подскажите куда копать?



0



313 / 312 / 221

Регистрация: 11.07.2015

Сообщений: 1,107

25.06.2017, 20:46

2



0



monah1983

0 / 0 / 1

Регистрация: 29.08.2013

Сообщений: 70

25.06.2017, 20:57

 [ТС]

3

Perl
1
2
[quote="plohoyav;10576825"]использовать готовый скрипт
Создание сессии сразу же после регистрации[/quote]

спасибо, но мне надо именно вот этот код



0



plohoyav

313 / 312 / 221

Регистрация: 11.07.2015

Сообщений: 1,107

25.06.2017, 21:04

4

если удалить

PHP
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if (!$db->query("SET a=1")) {
    printf("Errormessage: %s\n", $db->error);
}

исчезнет ошибка

PHP
1
Errormessage: Unknown system variable 'a'



0



Особый статус

623 / 221 / 164

Регистрация: 18.11.2015

Сообщений: 1,086

25.06.2017, 21:35

5

вроде бы вы сразу закрываете соединение с БД, а потом пытаетесь выполнить запрос уже без соединения, отсюда должны исчезнуть остальные 2 ошибки



0



0 / 0 / 1

Регистрация: 29.08.2013

Сообщений: 70

26.06.2017, 15:37

 [ТС]

6

c этим разобрался, спасибо))
чтобы новую тему не делать напишу здесь
вот тут есть пример ajax редактирования данных
но там отсутствует файл update_cell.php.
подскажите какой там содержание?



0



0 / 0 / 1

Регистрация: 29.08.2013

Сообщений: 70

27.06.2017, 09:29

 [ТС]

8

понятно. скрипт делает изменения, но данные в БД не заносятся. что можно сделать?



0



313 / 312 / 221

Регистрация: 11.07.2015

Сообщений: 1,107

27.06.2017, 18:19

9

firefox, правый клик, исследовать элемент, сеть

выбрать post запрос, посмотреть ответ сервера



0



I am creating a cursor for the first time.(referring this site)
I made this so far(

CREATE PROCEDURE `abc`.`cursordemo` (IN start_date DATETIME,IN end_date DATETIME)
BEGIN
DECLARE done INT DEFAULT FALSE;
  DECLARE k1,k2,g,s,last_status VARCHAR(45);
  DECLARE b, c INT;
  DECLARE cur1 CURSOR FOR SELECT `key` FROM `abc`.`temp_weekly`;
  DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;

OPEN cur1;
 read_loop: LOOP
    FETCH cur1 INTO k1;
    IF done THEN
      LEAVE read_loop;
    END IF;
    block_cursor:BEGIN
        DECLARE cur2 CURSOR FOR SELECT `key`,`group`,`status` FROM `abc`.`jira_local` WHERE `key` = k1 AND updateddate < end_date;
        DECLARE CONTINUE HANDLER FOR NOT FOUND SET done1 = TRUE;
        OPEN cur2;
        REPEAT
            FETCH cur2 INTO k2,g,s;
            IF NOT done1 THEN


            IF s != last_status THEN
                CASE
                    WHEN s = 'verified' THEN
                    SET c = c +1;
                    WHEN s = 'closed' THEN
                    SET c = c +1;
                    WHEN s = 'to be scheduled' THEN
                    SET c = c +1;
                    WHEN s = 'deferred' THEN
                    SET c = c +1;
/*'resolved','closed','to be scheduled','deferred','validated','assigned','l3 need more info','l2 need more info','need more info'*/
                    WHEN s = 'resolved' THEN
                    SET c = c +1;
                    WHEN s = 'validated' THEN
                    SET c = c +1;
                    WHEN s = 'assigned' THEN
                    SET c = c +1;
                    WHEN s = 'l3 need more info' THEN
                    SET c = c +1;
                    WHEN s = 'l2 need more info' THEN
                    SET c = c +1;
                    WHEN s = 'need more info' THEN
                    SET c = c +1;
                END CASE;
                SET last_status = s;
            END IF;
            END IF; 
        UNTIL NOT done1 END REPEAT;
        INSERT INTO ticketsResolvedCount values(k2,g,s,c);
    END block_cursor;

  END LOOP;

  CLOSE cur1;
  CLOSE cur2;
END$$

What I am doing
1) read all keys from temp_weekly and iterate
2) find all the records from jira_local table for a particular key and count the number of times it was verified,resolved etc.

Problem :
When I compile this it gives an error

ERROR 1193: Unknown system variable 'done1'

Also, I referred this link to create a stored procedure inside a loop

UPDATE:
After declaring done/done1 my procedure looks like this

BEGIN

      DECLARE k1,k2,g,s,last_status VARCHAR(45);
      DECLARE b, c INT;
      DECLARE cur1 CURSOR FOR SELECT `key` FROM `abc`.`temp_weekly`;
        DECLARE done1 BOOLEAN DEFAULT FALSE;
        DECLARE done BOOLEAN DEFAULT FALSE;
      DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
        .
        .
        .
block_cursor:BEGIN
        DECLARE cur2 CURSOR FOR SELECT `key`,`group`,`status` FROM `abc`.`jira_local` WHERE `key` = k1 AND updateddate < end_date;
        DECLARE CONTINUE HANDLER FOR NOT FOUND SET done1 = TRUE;
       .
       .
       .

this gives me

ERROR 1337: Variable or condition declaration after cursor or handler declaration

I’ve this simple table:

CREATE TABLE IF NOT EXISTS `testing`
(
    `testing_ID` INT UNSIGNED NOT NULL AUTO_INCREMENT,
    `meter` INT NOT NULL,
    `price` DECIMAL(12,2) NOT NULL,
    `price_per_meter` DECIMAL(10,2) NOT NULL,
    PRIMARY KEY (`testing_ID`)
)

And I’ve written this MySQL PROCEDURE:

DELIMITER $$
CREATE PROCEDURE `price_per_meter_calc` (price DECIMAL(12,2))
BEGIN
    SET price_per_meter = price/meter;
END
$$
DELIMITER ;

but I’ve got an error #1193 - Unknown system variable 'price_per_meter'. I believe it’s pretty straightforward code. What I want is simply MySQL to automatically calculate price_per_meter given the user will only insert price and meter values.

asked Mar 21, 2015 at 14:00

Cassie Kasandr's user avatar

0

You need to declare variable first and then only you can set the value.

Something like:

DECLARE price_per_meter DECIMAL(6,2);

Then other part is just logics.

answered Nov 3, 2018 at 2:36

Pharsa Thapa's user avatar

The Procedure fails to mention the table containing price_per_meter and meter.

Do you really want to feed in price? Do you want to store price in the table — if so, need another set. Or do you want to use the price that is already in the table — if so, don’t pass it in.

My recommendation is to completely erase the STORED PROCEDURE and start over. Think about what you «have» and what you «want to achieve», and what it takes to get from one to the other.

answered Mar 21, 2015 at 17:00

Rick James's user avatar

Rick JamesRick James

76.1k5 gold badges45 silver badges109 bronze badges

mysqli_error

(PHP 5, PHP 7, PHP 8)

mysqli::$errormysqli_errorВозвращает строку с описанием последней ошибки

Описание

Объектно-ориентированный стиль

Процедурный стиль

mysqli_error(mysqli $mysql): string

Возвращаемые значения

Строка с описанием ошибки. Пустая строка, если ошибки нет.

Примеры

Пример #1 Пример с $mysqli->error

Объектно-ориентированный стиль

<?php
$mysqli
= new mysqli("localhost", "my_user", "my_password", "world");/* Проверить соединение */
if ($mysqli->connect_errno) {
printf("Соединение не удалось: %s\n", $mysqli->connect_error);
exit();
}

if (!

$mysqli->query("SET a=1")) {
printf("Сообщение ошибки: %s\n", $mysqli->error);
}
/* Закрыть соединение */
$mysqli->close();
?>

Процедурный стиль

<?php
$link
= mysqli_connect("localhost", "my_user", "my_password", "world");/* Проверить соединение */
if (mysqli_connect_errno()) {
printf("Соединение не удалось: %s\n", mysqli_connect_error());
exit();
}

if (!

mysqli_query($link, "SET a=1")) {
printf("Сообщение ошибки: %s\n", mysqli_error($link));
}
/* Закрыть соединение */
mysqli_close($link);
?>

Результат выполнения данных примеров:

Сообщение ошибки: Unknown system variable 'a'

Смотрите также

  • mysqli_connect_errno() — Возвращает код ошибки последней попытки соединения
  • mysqli_connect_error() — Возвращает описание последней ошибки подключения
  • mysqli_errno() — Возвращает код ошибки последнего вызова функции
  • mysqli_sqlstate() — Возвращает код состояния SQLSTATE последней MySQL операции

information at saunderswebsolutions dot com

17 years ago

The mysqli_sql_exception class is not available to PHP 5.05

I used this code to catch errors
<?php
$query
= "SELECT XXname FROM customer_table ";
$res = $mysqli->query($query);

if (!

$res) {
printf("Errormessage: %s\n", $mysqli->error);
}
?>
The problem with this is that valid values for $res are: a mysqli_result object , true or false
This doesn't tell us that there has been an error with the sql used.
If you pass an update statement, false is a valid result if the update fails.

So, a better way is:
<?php
$query
= "SELECT XXname FROM customer_table ";
$res = $mysqli->query($query);

if (!

$mysqli->error) {
printf("Errormessage: %s\n", $mysqli->error);
}
?>

This would output something like:
Unexpected PHP error [mysqli::query() [<a href='function.query'>function.query</a>]: (42S22/1054): Unknown column 'XXname' in 'field list'] severity [E_WARNING] in [G:\database.php] line [249]

Very frustrating as I wanted to also catch the sql error and print out the stack trace.

A better way is:

<?php
mysqli_report
(MYSQLI_REPORT_OFF); //Turn off irritating default messages$mysqli = new mysqli("localhost", "my_user", "my_password", "world");$query = "SELECT XXname FROM customer_table ";
$res = $mysqli->query($query);

if (

$mysqli->error) {
try {
throw new
Exception("MySQL error $mysqli->error <br> Query:<br> $query", $msqli->errno);
} catch(
Exception $e ) {
echo
"Error No: ".$e->getCode(). " - ". $e->getMessage() . "<br >";
echo
nl2br($e->getTraceAsString());
}
}
//Do stuff with the result
?>
Prints out something like:
Error No: 1054
Unknown column 'XXname' in 'field list'
Query:
SELECT XXname FROM customer_table

#0 G:\\database.php(251): database->dbError('Unknown column ...', 1054, 'getQuery()', 'SELECT XXname F...')
#1 G:\data\WorkSites\1framework5\tests\dbtest.php(29): database->getString('SELECT XXname F...')
#2 c:\PHP\includes\simpletest\runner.php(58): testOfDB->testGetVal()
#3 c:\PHP\includes\simpletest\runner.php(96): SimpleInvoker->invoke('testGetVal')
#4 c:\PHP\includes\simpletest\runner.php(125): SimpleInvokerDecorator->invoke('testGetVal')
#5 c:\PHP\includes\simpletest\runner.php(183): SimpleErrorTrappingInvoker->invoke('testGetVal')
#6 c:\PHP\includes\simpletest\simple_test.php(90): SimpleRunner->run()
#7 c:\PHP\includes\simpletest\simple_test.php(498): SimpleTestCase->run(Object(HtmlReporter))
#8 c:\PHP\includes\simpletest\simple_test.php(500): GroupTest->run(Object(HtmlReporter))
#9 G:\all_tests.php(16): GroupTest->run(Object(HtmlReporter))

This will actually print out the error, a stack trace and the offending sql statement. Much more helpful when the sql statement is generated somewhere else in the code.

se (at) brainbits (dot) net

17 years ago

The decription "mysqli_error -- Returns a string description of the LAST error" is not exactly that what you get from mysqli_error. You get the error description from the last mysqli-function, not from the last mysql-error.

If you have the following situation

if (!$mysqli->query("SET a=1")) {
$mysqli->query("ROLLBACK;")
printf("Errormessage: %s\n", $mysqli->error);
}

you don't get an error-message, if the ROLLBACK-Query didn't failed, too. In order to get the right error-message you have to write:

if (!$mysqli->query("SET a=1")) {
printf("Errormessage: %s\n", $mysqli->error);
$mysqli->query("ROLLBACK;")
}

callforeach at gmail dot com

8 years ago

I had to set mysqli_report(MYSQLI_REPORT_ALL) at the begin of my script to be able to catch mysqli errors within the catch block of my php code.

Initially, I used the below code to throw and subsequent catch mysqli exceptions

<?php
try {
$mysqli = new mysqli('localhost','root','pwd','db');
if (
$mysqli->connect_errno)
throw new
Exception($mysqli->connect_error);

} catch (

Exception $e) {
echo
$e->getMessage();
}
I realized the exception was being thrown before the actual throw statement and hence the catch block was not being called.My current code looks like
mysqli_report
(MYSQLI_REPORT_ALL) ;
try {
$mysqli = new mysqli('localhost','root','pwd','db');
/* I don't need to throw the exception, it's being thrown automatically */} catch (Exception $e) {
echo
$e->getMessage();
}
This works fine and I'm able to trap all mysqli errors

asmith16 at littlesvr dot ca

9 years ago

Please note that the string returned may contain data initially provided by the user, possibly making your code vulnerable to XSS.

So even if you escape everything in your SQL query using mysqli_real_escape_string(), make sure that if you plan to display the string returned by mysqli_error() you run that string through htmlspecialchars().

As far as I can tell the two escape functions don't escape the same characters, which is why you need both (the first for SQL and the second for HTML/JS).

abderrahmanekaddour dot aissat at gmail dot com

1 year ago

<?php// The idea is the add formated errors information for developers to easier bugs detection.$myfile = fopen("database_log.log", "r");
$db = new mysqli("localhost", "root","root","data");
if(!
$db->query("SELECT")){
$timestamp = new DateTime();
$data_err = " {
\"title\": \" Select statement error \",
\"date_time\": "
.$timestamp->getTimestamp().",
\"error\":\" "
.$db->error." \"
} "
; // Do more information
fwrite($myfile, $data_err); // writing data
}
// In separate file do file read and format it for good visual.$db->close();
fclose($myfile);
?>

information at saunderswebsolutions dot com

17 years ago

Hi, you can also use the new mysqli_sql_exception to catch sql errors.
Example:
<?php
//set up $mysqli_instance here..
$Select = "SELECT xyz FROM mytable ";
try {
$res = $mysqli_instance->query($Select);
}catch (
mysqli_sql_exception $e) {
print
"Error Code <br>".$e->getCode();
print
"Error Message <br>".$e->getMessage();
print
"Strack Trace <br>".nl2br($e->getTraceAsString());
}
?>
Will print out something like
Error Code: 0
Error Message
No index used in query/prepared statement select sess_value from frame_sessions where sess_name = '5b85upjqkitjsostvs6g9rkul1'
Strack Trace:
#0 G:\classfiles\lib5\database.php(214): mysqli->query('select sess_val...')
#1 G:\classfiles\lib5\Session.php(52): database->getString('select sess_val...')
#2 [internal function]: sess_read('5b85upjqkitjsos...')
#3 G:\classfiles\includes.php(50): session_start()
#4 G:\tests\all_tests.php(4): include('G:\data\WorkSit...')
#5 {main}

Anonymous

3 years ago

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
try {
$this->connection = mysqli_connect($hostname,$username,$password, $dbname);
} catch (Exception $e) {
echo "Errno: " . mysqli_connect_errno() . PHP_EOL;
echo "Text error: " . mysqli_connect_error() . PHP_EOL;
exit;
}

Ok so i’m working on triggers, and it tells me it(MySQL workbench 5.2) doesn’t recognize this variable.
*Error Code: 1193. Unknown system variable error_msg_3*

I think it would be correct using it in a trigger, please help me

CREATE TRIGGER controlla_MaxCARDINALITA_INSERT
BEFORE INSERT ON SENTIERO__HA__TAPPA
FOR EACH ROW 
BEGIN

DECLARE max_cardinalita INTEGER;
DECLARE error_msg_3 CONDITION FOR SQLSTATE '99003';

SELECT COUNT(*) into max_cardinalita
FROM SENTIERO__HA__TAPPA
WHERE IDsentiero=NEW.IDsentiero;

IF max_cardinalita>=10 THEN
        SIGNAL error_msg_3;
        SET error_msg_3='INSERT: Il sentiero ha già il massimo numero di tappe consentito';

END IF;

END$$

EDIT ::

I tried this, and it seems working

DECLARE msg VARCHAR(255);
set msg = concat('MyTriggerError: Trying to insert a negative value in trigger_test: ');
signal sqlstate '45000' set message_text = msg;

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