Показать ошибки mysql

(PHP 4, PHP 5)

mysql_errorВозвращает текст ошибки последней операции с MySQL

Описание

mysql_error(resource $link_identifier = NULL): string

Список параметров

link_identifier

Соединение MySQL. Если идентификатор соединения не был указан,
используется последнее соединение, открытое mysql_connect(). Если такое соединение не было найдено,
функция попытается создать таковое, как если бы mysql_connect() была вызвана без параметров.
Если соединение не было найдено и не смогло быть создано, генерируется ошибка уровня E_WARNING.

Возвращаемые значения

Возвращает текст ошибки выполнения последней функции MySQL,
или '' (пустую строку), если операция
выполнена успешно.

Примеры

Пример #1 Пример использования mysql_error()

<?php
$link
= mysql_connect("localhost", "mysql_user", "mysql_password");mysql_select_db("nonexistentdb", $link);
echo
mysql_errno($link) . ": " . mysql_error($link). "\n";mysql_select_db("kossu", $link);
mysql_query("SELECT * FROM nonexistenttable", $link);
echo
mysql_errno($link) . ": " . mysql_error($link) . "\n";
?>

Результатом выполнения данного примера
будет что-то подобное:

1049: Unknown database 'nonexistentdb'
1146: Table 'kossu.nonexistenttable' doesn't exist

aleczapka _at) gmx dot net

19 years ago

If you want to display errors like "Access denied...", when mysql_error() returns "" and mysql_errno() returns 0, use $php_errormsg. This Warning will be stored there. You need to have track_errors set to true in your php.ini.

Note. There is a bug in either documentation about error_reporting() or in mysql_error() function cause manual for mysql_error(), says: "Errors coming back from the MySQL database backend no longer issue warnings." Which is not true.

Pendragon Castle

14 years ago

Using a manipulation of josh ><>'s function, I created the following. It's purpose is to use the DB to store errors. It handles both original query, as well as the error log. Included Larry Ullman's escape_data() as well since I use it in q().

<?php

function escape_data($data){

global
$dbc;

if(
ini_get('magic_quotes_gpc')){

$data=stripslashes($data);

}

return
mysql_real_escape_string(trim($data),$dbc);

}

function

q($page,$query){

// $page

$result = mysql_query($query);

if (
mysql_errno()) {

$error = "MySQL error ".mysql_errno().": ".mysql_error()."\n<br>When executing:<br>\n$query\n<br>";

$log = mysql_query("INSERT INTO db_errors (error_page,error_text) VALUES ('$page','".escape_data($error)."')");

}

}
// Run the query using q()

$query = "INSERT INTO names (first, last) VALUES ('myfirst', 'mylast'");

$result = q("Sample Page Title",$query);

?>

Florian Sidler

13 years ago

Be aware that if you are using multiple MySQL connections you MUST support the link identifier to the mysql_error() function. Otherwise your error message will be blank.

Just spent a good 30 minutes trying to figure out why i didn't see my SQL errors.

l dot poot at twing dot nl

17 years ago

When creating large applications it's quite handy to create a custom function for handling queries. Just include this function in every script. And use db_query(in this example) instead of mysql_query.

This example prompts an error in debugmode (variable $b_debugmode ). An e-mail with the error will be sent to the site operator otherwise.

The script writes a log file in directory ( in this case /log ) as well.

The system is vulnerable when database/query information is prompted to visitors. So be sure to hide this information for visitors anytime.

Regars,

Lennart Poot
http://www.twing.nl

<?php
$b_debugmode
= 1; // 0 || 1$system_operator_mail = 'developer@company.com';
$system_from_mail = 'info@mywebsite.com';

function

db_query( $query ){
global
$b_debugmode;// Perform Query
$result = mysql_query($query);// Check result
// This shows the actual query sent to MySQL, and the error. Useful for debugging.
if (!$result) {
if(
$b_debugmode){
$message = '<b>Invalid query:</b><br>' . mysql_error() . '<br><br>';
$message .= '<b>Whole query:</b><br>' . $query . '<br><br>';
die(
$message);
}
raise_error('db_query_error: ' . $message);
}
return
$result;
}

function

raise_error( $message ){
global
$system_operator_mail, $system_from_mail;$serror=
"Env: " . $_SERVER['SERVER_NAME'] . "\r\n" .
"timestamp: " . Date('m/d/Y H:i:s') . "\r\n" .
"script: " . $_SERVER['PHP_SELF'] . "\r\n" .
"error: " . $message ."\r\n\r\n";// open a log file and write error
$fhandle = fopen( '/logs/errors'.date('Ymd').'.txt', 'a' );
if(
$fhandle){
fwrite( $fhandle, $serror );
fclose(( $fhandle ));
}
// e-mail error to system operator
if(!$b_debugmode)
mail($system_operator_mail, 'error: '.$message, $serror, 'From: ' . $system_from_mail );
}
?>

Anonymous

22 years ago

some error can't handle. Example:

ERROR 1044: Access denied for user: 'ituser@mail.ramon.intranet' to database 'itcom'

This error ocurrs when a intent of a sql insert of no authorized user. The results: mysql_errno = 0 and the mysql_error = "" .

Anonymous

18 years ago

My suggested implementation of mysql_error():

$result = mysql_query($query) or die("<b>A fatal MySQL error occured</b>.\n<br />Query: " . $query . "<br />\nError: (" . mysql_errno() . ") " . mysql_error());

This will print out something like...

A fatal MySQL error occured.

Query: SELECT * FROM table

Error: (err_no) Bla bla bla, you did everything wrong

It's very useful to see your query in order to detect problems with syntax. Most often, the output message from MySQL doesn't let you see enough of the query in the error message to let you see where your query went bad- it a missing quote, comma, or ( or ) could have occured well before the error was detected. I do -not- recomend using this procedure, however, for queries which execute on your site that are not user-specific as it has the potential to leak sensative data. Recomended use is just for debugging/building a script, and for general user-specific queries which would at the worst, leak the users own information to themself.

Good luck,

-Scott

olaf at amen-online dot de

19 years ago

When dealing with user input, make sure that you use
<?php
echo htmlspecialchars (mysql_error ());
?>
instead of
<?php
echo mysql_error ();
?>

Otherwise it might be possible to crack into your system by submitting data that causes the SQL query to fail and that also contains javascript commands.

Would it make sense to change the examples in the documentation for mysql_query () and for mysql_error () accordingly?

josh ><>

19 years ago

Oops, the code in my previous post only works for queries that don't return data (INSERT, UPDATE, DELETE, etc.), this updated function should work for all types of queries (using $result = myquery($query);):

function myquery ($query) {
$result = mysql_query($query);
if (mysql_errno())
echo "MySQL error ".mysql_errno().": ".mysql_error()."\n<br>When executing:<br>\n$query\n<br>";
return $result;
}

Gianluigi_Zanettini-MegaLab.it

16 years ago

A friend of mine proposed a great solution.

<?php
$old_track
= ini_set('track_errors', '1');

.....

if (

$this->db_handle!=FALSE && $db_selection_status!=FALSE)
{
$this->connected=1;
ini_set('track_errors', $old_track);
}
else
{
$this->connected=-1;
$mysql_warning=$php_errormsg;
ini_set('track_errors', $old_track);
throw new
mysql_cns_exception(1, $mysql_warning . " " . mysql_error());
}
?>

scott at rocketpack dot net

20 years ago

My suggested implementation of mysql_error():

$result = mysql_query($query) or die("<b>A fatal MySQL error occured</b>.\n<br />Query: " . $query . "<br />\nError: (" . mysql_errno() . ") " . mysql_error());

This will print out something like...

<b>A fatal MySQL error occured</b>.
Query: SELECT * FROM table
Error: (err_no) Bla bla bla, you did everything wrong

It's very useful to see your query in order to detect problems with syntax. Most often, the output message from MySQL doesn't let you see enough of the query in the error message to let you see where your query went bad- it a missing quote, comma, or ( or ) could have occured well before the error was detected. I do -not- recomend using this procedure, however, for queries which execute on your site that are not user-specific as it has the potential to leak sensative data. Recomended use is just for debugging/building a script, and for general user-specific queries which would at the worst, leak the users own information to themself.

Good luck,

-Scott

Gianluigi_Zanettini-MegaLab.it

16 years ago

"Errors coming back from the MySQL database backend no longer issue warnings." Please note, you have an error/bug here. In fact, MySQL 5.1 with PHP 5.2:

Warning: mysql_connect() [function.mysql-connect]: Unknown MySQL server host 'locallllllhost' (11001)

That's a warning, which is not trapped by mysql_error()!

phpnet at robzazueta dot com

16 years ago

This is a big one - As of MySQL 4.1 and above, apparently, the way passwords are hashed has changed. PHP 4.x is not compatible with this change, though PHP 5.0 is. I'm still using the 4.x series for various compatibility reasons, so when I set up MySQL 5.0.x on IIS 6.0 running PHP 4.4.4 I was surpised to get this error from mysql_error():

MYSQL: Client does not support authentication protocol requested by server; consider upgrading MySQL client

According to the MySQL site (http://dev.mysql.com/doc/refman/5.0/en/old-client.html) the best fix for this is to use the OLD_PASSWORD() function for your mysql DB user. You can reset it by issuing to MySQL:

Set PASSWORD for 'user'@'host' = OLD_PASSWORD('password');

This saved my hide.

miko_il AT yahoo DOT com

19 years ago

Gerrit

9 years ago

The following code returns two times the same error, even though I would have expected only one:

$ conn = mysql_connect ('localhost', 'root', '');
$ conn2 = mysql_connect ('localhost', 'root', '');

mysql_select_db ('db1', $ conn);
mysql_select_db ('db2', $ conn2);

$ result = mysql_query ("select 1 from dual", $ conn);
$ result2 = mysql_query ("select 1 from luad", $ conn2);

echo mysql_error ($ conn) "<hr>".
echo mysql_error ($ conn2) "<hr>".

The reason for this is that mysql_connect not working as expected a further connection returns. Since the parameters are equal, a further reference to the previous link is returned. So also changes the second mysql_select_db the selected DB of $conn to 'db2'.

If you change the connection parameters of the second connection to 127.0.0.1, a new connection is returned. In addition to the parameters new_link the mysql_connect() function to be forced.

Summary: in this tutorial, you will learn how to use the MySQL SHOW ERRORS statement to display error information generated by a query.

Introduction to MySQL SHOW ERRORS statement

The SHOW ERRORS is a diagnostic statement that displays information for errors.

The SHOW ERRORS is similar to the SHOW WARNINGS except that it shows only errors, not warnings and notes.

The following SHOW ERRORS displays all errors:

SHOW ERRORS;
Code language: SQL (Structured Query Language) (sql)

To limit the number of errors to return, you use the SHOW ERRORS LIMIT statement:

SHOW ERRORS [LIMIT [offset,] row_count];
Code language: SQL (Structured Query Language) (sql)

The LIMIT clause has the same meaning as for the SELECT statement.

To get the total number of errors, you use the following form of the SHOW ERRORS statement:

SHOW COUNT(*) ERRORS;
Code language: SQL (Structured Query Language) (sql)

Or you can select it from the system variable @@error_count:

SELECT @@error_count;
Code language: SQL (Structured Query Language) (sql)

MySQL SHOW ERRORS statement example

This statement returns id from the products table in the sample database:

SELECT id FROM products;
Code language: SQL (Structured Query Language) (sql)

However, the products table does not have the id column.

To show the error, you use the SHOW ERRORS statement:

SHOW ERRORS;
Code language: SQL (Structured Query Language) (sql)

To get the total number of errors, you use the error_count variable:

SELECT @@error_count;
Code language: SQL (Structured Query Language) (sql)

In this tutorial, you will have learned how to use the MySQL SHOW ERRORS statement to display error information.

Was this tutorial helpful?

i am unable to get the last 2 echos to work, even if the update query fails it still displays success. If anyone has any suggestions on this code to be improved on any line, please do!

<?php
        if(!empty($_POST['username']) && !empty($_POST['answer']))  { 
            $username = $_POST['username'];
            $idfetch = mysql_query("SELECT id FROM users WHERE username ='$username'") //check it
            or die(mysql_error());
            $fetched = mysql_fetch_array($idfetch);  
            $id = $fetched['id']; //get users id for checking
            $answer = $_POST['answer'];
            $password = (mysql_real_escape_string($_POST['password']));
            $confpass = (mysql_real_escape_string($_POST['confpass']));
            if ($password != $confpass) {
                echo ("Passwords do not match, please try again.");
                exit;
            }
            $updatequery = mysql_query("UPDATE users SET PASSWORD='$password' WHERE id='$id' AND username='$username' AND answer='$answer'");
            if($updatequery)  {  
                echo "<h1>Success</h1>";  
                echo "<p>Your account password was successfully changed. Please <a href=\"login.php\">click here to login</a>.</p>";  
            }  
            else  {  
                echo "<h1>Error</h1>";  
                echo "<p>Sorry, but a field was incorrect.</p>";  
            }  
       } 
?>

Thanks in advance!

Sterling Archer's user avatar

asked Dec 17, 2012 at 6:34

sparkones's user avatar

4

mysql_query("UPDATE users SET PASSWORD='$password' WHERE id='$id' AND username='$username' AND answer='$answer'") or die(mysql_error()."update failed");

and use

mysql_affected_rows()

Returns the number of affected rows on success, and -1 if the last query failed.

answered Dec 17, 2012 at 6:48

Arun Killu's user avatar

Arun KilluArun Killu

13.6k5 gold badges34 silver badges61 bronze badges

use try catch and try to get the error enable error reporting in php also

<?php
        error_reporting(E_ALL);
        ini_set('display_errors','On');
        if(!empty($_POST['username']) && !empty($_POST['answer']))  { 
        $username = $_POST['username'];
        $idfetch = mysql_query("SELECT id FROM users WHERE username ='$username'") //check it
        or die(mysql_error());
        $fetched = mysql_fetch_array($idfetch);  
        $id = $fetched['id']; //get users id for checking
        $answer = $_POST['answer'];
        $password = (mysql_real_escape_string($_POST['password']));
        $confpass = (mysql_real_escape_string($_POST['confpass']));
        if ($password != $confpass) {
        echo ("Passwords do not match, please try again.");
        exit;}

        try{
        $updatequery = mysql_query("UPDATE users SET PASSWORD='$password' WHERE id='$id' AND username='$username' AND answer='$answer'");
        if($updatequery)  {  
        echo "<h1>Success</h1>";  
        echo "<p>Your account password was successfully changed. Please <a href=\"login.php\">click here to login</a>.</p>";  }  
        else  {  
        echo "<h1>Error</h1>";  
        echo "<p>Sorry, but a field was incorrect.</p>";  
        }  

        }catch(Exception $e){
            print_R($e);
        }
        }

answered Dec 17, 2012 at 6:40

Akhilraj N S's user avatar

Akhilraj N SAkhilraj N S

9,0595 gold badges36 silver badges43 bronze badges

use or die(mysql_error()) as it will display mysql error if there is an error with your query.

$updatequery = mysql_query("UPDATE users SET PASSWORD='$password' WHERE id='$id' AND username='$username' AND answer='$answer'") or die(mysql_error());

answered Dec 17, 2012 at 6:38

sicKo's user avatar

sicKosicKo

1,2411 gold badge12 silver badges35 bronze badges

Try this:

$idfetch = mysql_query("SELECT id FROM users WHERE username ='$username'");
if(!idfetch){
  die(mysql_error());
}

Do the same for all other queries too.

answered Dec 17, 2012 at 6:43

Chetana Kestikar's user avatar

try this, first count the row count value its great 1 then proceed the login process.

<?php
    if(!empty($_POST['username']) && !empty($_POST['answer']))  { 
        $username = $_POST['username'];
        $idfetch = mysql_query("SELECT id FROM users WHERE username ='$username'") //check it
        or die(mysql_error());
        $fetched = mysql_fetch_array($idfetch);

        $count= mysql_num_rows($idfetch);

        if($count>0){
        $id = $fetched['id']; //get users id for checking
        $answer = $_POST['answer'];
        $password = (mysql_real_escape_string($_POST['password']));
        $confpass = (mysql_real_escape_string($_POST['confpass']));
        if ($password != $confpass) {
            echo ("Passwords do not match, please try again.");
            exit;
        }

        $updatequery = mysql_query("UPDATE users SET PASSWORD='$password' WHERE id='$id' AND username='$username' AND answer='$answer'");

          if($updatequery)  {  
            echo "<h1>Success</h1>";  
            echo "<p>Your account password was successfully changed. Please <a href=\"login.php\">click here to login</a>.</p>";  
         }  
           else  {  
             echo "<h1>Error</h1>";  
             echo "<p>Sorry, but a field was incorrect.</p>";  
           }  
   } } ?>

answered Dec 17, 2012 at 6:48

RaJeSh's user avatar

RaJeShRaJeSh

3133 silver badges14 bronze badges

Use

if(mysql_num_rows($updatequery)  > 0) {
    // success
} else {
    // error
}

$updatequery will always be true (not NULL), until there is an error in your query

answered Dec 17, 2012 at 6:36

Stefan Fandler's user avatar

2

Error message displaying after execution of a query

MySQL Error
We can display error message in case of an error generated by MySQL query. This meaning full error message gives idea one the problem or bugs in the script. We can print the error message by using mysql function mysql_error(). This function returns the error message associated with most recently executed query. So it is a good idea to check for error before going to next query. We can even add the error number returned by mysql to this error message. This way we can generate a meaningful detail on the bugs on the script.

$querry = mysql_query("SELECT new_field FROM student");

echo "Error message = ".mysql_error();

In our student table there is no field as new_field. Here here is the message we will get

Error message = Unknown column 'new_field' in 'field list'

Note that mysql_error() is deprecated as of PHP 5.5.0 so better to avoid using this function. So if you are using PDO then we can use errorInfo() to display the returned error message from MySQL

Here is a sample code in PHP using PDO to display record and on failure to display error message.

require 'config-pdo.php'; // database connection string 
$pdo=$dbo->prepare('Select no_name from student');
if($pdo->execute()){
echo 'Success<br>';
$row = $pdo->fetch(PDO::FETCH_OBJ);
echo "Name : $row->name ";
}else{
print_r($pdo->errorInfo());
}

In the above code there is an error in sql , there is no column by name no_name. The output will be

Array ( [0] => 42S22 [1] => 1054 [2] => Unknown column 'no_name' in 'field list' )

So to get correct result change the sql part like this .

$pdo=$dbo->prepare('Select * from student');

With this you will get desired output.

Handling PDO errors

If such error occurs what is to be done ? We have three options to handle in case of errors.

We can stop the execution of the script. ( Fatal error : stop execution of code )
We can display warning message ( Warning only, display message and no stoppage of execution )
Remain silent ( continue to execute and display error message if required )

Setting the PDO error handling attribute.

We can use setAttribute to tell how to handle the PDO errors.
Here is a sample

$dbo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING);   // gives warning only

Here is the complete code.

require 'config-pdo.php'; // database connection string 
//$dbo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); // generates fatal error
//$dbo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING);   // gives warning only
$dbo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_SILENT);  // remain silent 
 
$pdo=$dbo->prepare('Select no_name from student');
if($pdo->execute()){
echo 'Success<br>';
$row = $pdo->fetch(PDO::FETCH_OBJ);
echo "Name : $row->name ";
}else{
print_r($pdo->errorInfo());
}

Now we have given all the three options but commented two and set the attribute to Silent. You can change the commented status and see how the script is behaving in different setAttribute values.

It is clear that the above code will generate error message. We can store the error message in a database or we can post ( by mail ) to the programmer about these details.

Store the error message generated in an sql query or send email >>

PHP MySQL functions
MySQL Error Number
MySQL Error Mail

plus2net.com

dealer pulsa

28-05-2010

thanks for sharing, It’s usefull for me
Sofie

30-11-2012

Failed to read auto-increment value from storage engine
  1. PHP MySQLi Error Functions
  2. Conclusion

Display Errors Using MySQLi Error Functions

MySQLi is a PHP function used to access the MySQL database server. You can use this extension if you have MySQL version 4.1.13 or above.

There are various MySQLi functions that you can use to perform different functions in PHP. In this article, we will learn MySQLi error functions.

We will also see how and where to use code examples and observe the outputs. For this tutorial, we will use MySQL version 8.0.27 and PHP version 7.4.1.

PHP MySQLi Error Functions

In this tutorial, we will learn about the following PHP MySQLi error functions:

  • mysqli_error()
  • mysqli_errno()
  • mysqli_error_list()
  • mysqli_connect_error()
  • mysqli_connect_errno()

All these functions can be used in object-oriented style and procedural style. Let’s understand both syntax using the mysqli_error() function.

Syntax of mysqli_error() Function in Object Oriented Style

Syntax of mysqli_error() Function in Procedural Style

string mysqli_error ( mysqli $link )

mysqli_error() Function in MySQL

This function is used to output the last error description for the most recent function call (if there is any). It is used when you want to know whether the SQL query has an error or not.

mysqli_error() returns the error description and empty string if there is no error. See the following example.

Example Code Using Procedural Style:

<?php
    $host = "localhost";
    $username = "root";
    $password = "";
    $database = "person";

    $connection = mysqli_connect($host, $username, $password, $database) 
    or die("Connection Failed"); 

    $sql = "SELECT * FROM teacher";
    $result = mysqli_query($connection, $sql);
    $error_message = mysqli_error($connection);

    if($error_message == ""){
        echo "No error related to SQL query.";
    }else{
        echo "Query Failed: ".$error_message;
    }
    mysqli_close($connection);
?>

The code given above tries to make the connection using $host, $username, $password, $database variables and save this connection into the $connection variable.

mysqli_error() function will take this connection variable $connection as a parameter and check if there is any error caused by the recent MySQLi function call which is mysqli_query($connection, $sql) here.

Output:

display errors using mysqli error functions - no error using mysqli_error

Now, change the table name in the SQL query from teacher to person and observe the output given below.

Output:

display errors using mysqli error functions - error using mysqli_error

We, as a developer, can easily understand that there is no person table in the person database (this is what it means in the above error).

Keep the table name changed and replace the line $error_message = mysqli_error($connection); with $error_message = $connection->error; to practice and understand the object oriented style using MySQLi error function.

mysqli_errno() Function in MySQL

mysqli_errno() works the same as mysqli_error() does, but it will return the error code instead of the error description.

Write the following code to practice and understand. You may have noticed that we use a procedural style to practice this function.

<?php
     $host = "localhost";
     $username = "root";
     $password = "";
     $database = "person";

     $connection = mysqli_connect($host, $username, $password, $database) 
     or die("Connection Failed"); 

     $sql = "SELECT * FROM person";
     $result = mysqli_query($connection, $sql);
     $error_message = mysqli_errno($connection);

     if($error_message == ""){
     	echo "No error related to SQL query.";
     }else{
     	echo "Query Failed: ".$error_message;
     }
    mysqli_close($connection);
?>

The code given above will show the following output where you will see a number as an error code.

Output:

display errors using msyqli error functions - error using mysqli_errno

The question is, why do we use this function to show the numbers only? Because if you want to print a user-friendly error message (custom message), you can use this error code in if-else statements.

See the following code and its output below.

<?php
     $host = "localhost";
     $username = "root";
     $password = "";
     $database = "person";

     $connection = mysqli_connect($host, $username, $password, $database) 
     or die("Connection Failed"); 

     $sql = "SELECT * FROM person";
     $result = mysqli_query($connection, $sql);
     $error_message = mysqli_errno($connection);

     if($error_message == 1146){
     	echo "You are trying to read the data from a table which doesn't exist in your 			database "."'".$database."'";
     }
    mysqli_close($connection);
?>

Output:

display errors using mysqli error functions - custom error message using mysqli_errno.png

mysqli_error_list() Function in MySQL

This function is very useful for knowing the error code, SQL state, and error description because this function returns an array containing all the necessary information.

Example Code:

<?php
     $host = "localhost";
     $username = "root";
     $password = "";
     $database = "person";

     $connection = mysqli_connect($host, $username, $password, $database) 
     or die("Connection Failed"); 

     $sql = "SELECT * FROM person";
     $result = mysqli_query($connection, $sql);
     print_r(mysqli_error_list($connection));
     mysqli_close($connection);
?>

Output:

display errors using mysqli error functions - error list using mysqli_error_list

mysqli_connect_error() Function in MySQL

mysqli_connect_error() returns the error description from the last connection if there is any. Although, the die() function also tell about the unsuccessful connection but mysqli_connect_error() returns the error that we can understand easily.

Write the following code first, see its output, and then we’ll compare it with the output produced by mysqli_connect_error().

<?php
     $host = "localhost";
     $username = "root";
     $password = "";
     $database = "person";

     $connection = mysqli_connect($host, $username, $password, $database) 
     or die("Connection Failed"); 

     $sql = "SELECT * FROM person";
     $result = mysqli_query($connection, $sql);
     $error_message = mysqli_error($connection);

     if($error_message != ""){
     	echo "Query Failed: ".$error_message;
      }
    mysqli_close($connection);
?>

Output:

display errors using mysqli error functions - error using mysqli_connect_error part a

See the output given above; you can see that the error we can understand is somewhere in the middle.

Imagine, if you have 2 or 3 errors, it would not be easy to find out. Now, use the mysqli_connect_error() and see the difference using the following code and output.

<?php
     $host = "localhost";
     $username = "newroot";
     $password = "";
     $database = "person";

     $connection = mysqli_connect($host, $username, $password, $database) 
     or die("Connection Failed: ".mysqli_connect_error()); 

     $sql = "SELECT * FROM teacher";
     $result = mysqli_query($connection, $sql);
     $error_message = mysqli_error($connection);

     if($error_message != ""){
     	echo "SQL Query Failed: ".$error_message;
    }
    mysqli_close($connection);
?>

Output:

display errors using mysqli error functions - error using mysqli_connect_error part b

The above output clearly says that there is no user named newroot, which does not allow you to access the database.

mysqli_connect_errno() Function in MySQL

This function behaves like mysqli_connect_error() but displays the error code rather than the error message. We can use this error code to write custom error messages.

Example Code:

<?php
     $host = "localhost";
     $username = "newroot";
     $password = "";
     $database = "person";

     $connection = mysqli_connect($host, $username, $password, $database) 
     or die("Connection Failed: ".mysqli_connect_errno()); 

     $sql = "SELECT * FROM teacher";
     $result = mysqli_query($connection, $sql);
     $error_message = mysqli_error($connection);

     if($error_message != ""){
	     echo "SQL Query Failed: ".$error_message;
     }
     mysqli_close($connection);
?>

Output:

display errors using mysqli error functions - error using mysqli_connect_errno

Conclusion

Considering all the discussion and examples, we have concluded two main categories. The first category shows the errors about SQL queries and the other about database connections.

Depending on the project needs, we can print the error message or the error code in each category.

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