Ошибка json parse anonymous - Решение и исправление самых разных ошибок на TopOshibok.ru

I do not understand what went wrong when parsing file:

{ "t": -9.30, "p": 728.11, "h": 87.10 }

javascript code:

<script type="text/javascript">
function check() {
    $.get("http://....file.json", function(response, status, xhr) {
        if (status == "success") {
            var json = JSON.parse(response);
            $("#temp").html(json.t + "&deg;");
            $("#pressure").html(json.p + " mm hg");
        }
        if (status == "error") {
            $("#temp").html("error");
        }
    });
}

I receive error:

SyntaxError: JSON Parse error: Unexpected identifier "object"

asked Dec 18, 2013 at 14:09

Most probably your response is already a JavaScript object and it not required to be parsed.

Remove the line var json = JSON.parse(response); and your code should work.

answered Dec 18, 2013 at 14:11

VisioNVisioN

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According to the jQuery docs on $.ajax (which is what $.get uses internally):

dataType: …If none is specified, jQuery will try to infer it based on the MIME type of the response (an XML MIME type will yield XML, in 1.4 JSON will yield a JavaScript object…)

Thus, your response is likely already an object. When you do JSON.parse(response), you’re really doing

JSON.parse("[object Object]")

because JSON.parse coerces its argument to a string, and plain objects by default stringify to [object Object]. The initial [ leads JSON.parse to expect an array, but it then chokes on the object token, which does not fit the JSON grammar.

Remove the JSON.parse line, because response is already parsed into an object by jQuery.

answered Dec 18, 2013 at 14:16

apsillersapsillers

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Источник

I do not understand what went wrong when parsing file:

{ "t": -9.30, "p": 728.11, "h": 87.10 }

javascript code:

<script type="text/javascript">
function check() {
    $.get("http://....file.json", function(response, status, xhr) {
        if (status == "success") {
            var json = JSON.parse(response);
            $("#temp").html(json.t + "&deg;");
            $("#pressure").html(json.p + " mm hg");
        }
        if (status == "error") {
            $("#temp").html("error");
        }
    });
}

I receive error:

SyntaxError: JSON Parse error: Unexpected identifier "object"

asked Dec 18, 2013 at 14:09

Most probably your response is already a JavaScript object and it not required to be parsed.

Remove the line var json = JSON.parse(response); and your code should work.

answered Dec 18, 2013 at 14:11

VisioNVisioN

143k32 gold badges282 silver badges281 bronze badges

According to the jQuery docs on $.ajax (which is what $.get uses internally):

dataType: …If none is specified, jQuery will try to infer it based on the MIME type of the response (an XML MIME type will yield XML, in 1.4 JSON will yield a JavaScript object…)

Thus, your response is likely already an object. When you do JSON.parse(response), you’re really doing

JSON.parse("[object Object]")

Remove the JSON.parse line, because response is already parsed into an object by jQuery.

answered Dec 18, 2013 at 14:16

apsillersapsillers

113k17 gold badges235 silver badges239 bronze badges

Источник

The «SyntaxError: JSON Parse error: Unexpected identifier ‘object’ (anonymous function)» error is thrown in JavaScript when JSON.parse() method is used to parse a string that is not a valid JSON string. The error message indicates that the string being parsed contains an unexpected identifier, in this case «object». This issue can be caused by a number of factors, including incorrect data type conversion or incorrect data formatting in the input string. In this article, we will discuss different methods to fix this error and successfully parse a JSON string in JavaScript.

Method 1: Verify the input string

To fix the «SyntaxError: JSON Parse error: Unexpected identifier ‘object'» in Javascript, you can use the «Verify the input string» method. This involves checking the input string before parsing it as JSON to ensure it is a valid JSON string. Here’s an example code:

function parseJsonString(jsonString) {
  let jsonObject;
  
  try {
    jsonObject = JSON.parse(jsonString);
  } catch (e) {
    if (e instanceof SyntaxError) {
      const sanitizedJsonString = jsonString
        .replace(/\\(?:["\\\/bfnrt]|u[0-9a-fA-F]{4})/g, '@')
        .replace(/"[^"\\\n\r]*"|true|false|null|-?\d+(?:\.\d*)?(?:[eE][+\-]?\d+)?/g, ']')
        .replace(/(?:^|:|,)(?:\s*\[)+/g, '');

      try {
        jsonObject = JSON.parse(sanitizedJsonString);
      } catch (e) {
        throw new Error('Invalid JSON string');
      }
    } else {
      throw e;
    }
  }

  return jsonObject;
}

This function takes a JSON string as input and returns the parsed JSON object. It first tries to parse the input string using the standard JSON.parse() method. If it encounters a syntax error, it replaces any problematic characters in the string and tries parsing it again. If it still encounters an error, it throws an error indicating that the input string is invalid.

Here’s an example usage of the function:

const jsonString = '{"name": "John", "age": 30, "city": "New York"}';
const jsonObject = parseJsonString(jsonString);

console.log(jsonObject); // {name: "John", age: 30, city: "New York"}

In this example, the function successfully parses the input JSON string and returns the corresponding JSON object.

Note that this method is not foolproof and may not catch all possible syntax errors in a JSON string. It is always best to ensure that the input string is valid JSON before attempting to parse it.

Method 2: Use try-catch block

To fix the SyntaxError: JSON Parse error: Unexpected identifier "object" error in JavaScript, you can use a try-catch block to handle the error. The try block contains the code that may throw an error, while the catch block handles the error if it occurs.

Here is an example code that shows how to use a try-catch block to fix the error:

try {
  const jsonString = '{"name": "John", "age": 30, "city": "New York"}';
  const person = JSON.parse(jsonString);
  console.log(person);
} catch (error) {
  console.error(error);
}

In the above code, we try to parse a JSON string using the JSON.parse() method. If the parsing is successful, the parsed object is logged to the console. However, if there is an error, the error is caught in the catch block, and the error message is logged to the console.

Here is another example that shows how to handle the error when parsing an invalid JSON string:

try {
  const jsonString = '{name: "John", age: 30, city: "New York"}';
  const person = JSON.parse(jsonString);
  console.log(person);
} catch (error) {
  console.error(error);
}

In this example, the JSON string is invalid because the object keys are not enclosed in double quotes. When we try to parse the string, we get the SyntaxError: JSON Parse error: Unexpected identifier "name" error. However, the error is caught in the catch block, and the error message is logged to the console.

In summary, using a try-catch block is an effective way to handle errors when parsing JSON strings in JavaScript. By catching the error, you can gracefully handle the error and prevent your application from crashing.

Method 3: Stringify the JSON object before parsing

To fix the «SyntaxError: JSON Parse error: Unexpected identifier ‘object'» error in JavaScript, you can use the JSON.stringify() method to convert the JSON object to a string before parsing it with JSON.parse(). Here’s an example:

const jsonString = '{"name": "John", "age": 30, "city": "New York"}';
const jsonObject = JSON.parse(jsonString); // Throws SyntaxError

const fixedObject = JSON.parse(JSON.stringify(jsonString)); // Converts JSON object to string and then parses it
console.log(fixedObject); // Output: {name: "John", age: 30, city: "New York"}

In this example, we have a JSON string that we want to parse into a JavaScript object. However, when we try to parse it using JSON.parse(), we get a SyntaxError because the JSON object is not a valid string.

To fix this error, we use JSON.stringify() to convert the JSON object to a string before parsing it with JSON.parse(). This ensures that the JSON object is a valid string that can be parsed into a JavaScript object.

Note that this method can also be used when working with AJAX requests and APIs that return JSON data. Here’s an example:

fetch('https://api.example.com/data')
  .then(response => response.json())
  .then(data => {
    const fixedData = JSON.parse(JSON.stringify(data));
    console.log(fixedData);
  })
  .catch(error => console.error(error));

In this example, we make an AJAX request to an API that returns JSON data. We use the response.json() method to parse the JSON data into a JavaScript object. However, if the JSON data is not a valid string, we will get the SyntaxError error.

To fix this error, we use JSON.stringify() to convert the JSON object to a string before parsing it with JSON.parse(). This ensures that the JSON data is a valid string that can be parsed into a JavaScript object.

Method 4: Check for special characters in the string

If you are encountering a SyntaxError: JSON Parse error: Unexpected identifier "object" in your anonymous function, it may be due to special characters in your string. To check for special characters in your string, you can use the JSON.stringify() method to convert your object to a string, then use a regular expression to match any non-ASCII characters.

Here’s an example:

const myObject = { name: "John", age: 30, city: "New York" };
const myString = JSON.stringify(myObject);

if (/[^ -~\t\n\r]/.test(myString)) {
  // special characters found
  console.log("Special characters found in string:", myString);
} else {
  // no special characters found
  console.log("No special characters found in string:", myString);
}

In this example, we first define an object myObject with some properties. We then use JSON.stringify() to convert myObject to a string, which we store in myString. We then use a regular expression /[^ -~\t\n\r]/ to match any characters that are not printable ASCII characters (i.e. special characters), and test it against myString. If any special characters are found, the code logs a message to the console.

Note that the regular expression [^ -~\t\n\r] matches any character that is not a printable ASCII character (i.e. any character that is not in the range of space to tilde, as well as tab, newline, and carriage return). You can modify this regular expression to match other types of special characters if needed.

By checking for special characters in your string, you can identify and remove any non-ASCII characters that may be causing the SyntaxError: JSON Parse error: Unexpected identifier "object" in your anonymous function.

Источник

Uncaught SyntaxError: Unexpected end of JSON input is a JavaScript error message, occurs when the user tries to parse an invalid/incomplete JSON string using JSON.parse().

This short article will try to clarify a few things about the error and possible steps to fix it.

The full form of the message would look like this:

Uncaught SyntaxError: Unexpected end of JSON input
at JSON.parse (<anonymous>)
at <your-script-name.js>Code language: JavaScript (javascript)

Unexpected end of JSON input in Chrome console

“Unexpected end of JSON input” root cause is a malformed string passed into the JSON.parse() method.

In most cases, it is due to a missing character in the last position of a JSON string that wraps its objects (such as a closing square bracket [] or curly bracket {}).

Sometimes, you may be trying to read an empty JSON file. A valid empty JSON file would still need to have curly brackets to indicate that it contains an empty object.

// empty.json file contents
{}Code language: JSON / JSON with Comments (json)

Let’s look at two examples below to clearly understand what’s missing

	Malformed JSON parsing	Corrected JSON parsing.
1	`var my_json_string = '{"prop1": 5, "prop2": "New York"';` `var data = JSON.parse(my_json_string);`	`var my_json_string = '{"prop1": 5, "prop2": "New York"}';` `var data = JSON.parse(my_json_string);`
2	`var my_json_string = '[1, "yellow", 256, "black"';` `var data = JSON.parse(my_json_string);`	`var my_json_string = '[1, "yellow", 256, "black"]';` `var data = JSON.parse(my_json_string);`

In the first example, there’s a missing closing curly bracket at the end of the string. Meanwhile, the second example demonstrate a malformed JSON string with the closing square bracket truncated.

Debug and fix `Unexpected end of JSON input`

Locate a statement using the JSON.parse() method. If you’re on the browser’s console, click on the last line of the exception message (which is a reference to the code block that raised that exception). The browser will then bring you to the actual source code.
Inspect the input of JSON.parse(). You can take a close look at the data to spot the error, or use a JSON linter/JSON validator. Usually the errors are in the beginning or the end of the string.
If the error message is SyntaxError: unexpected end of JSON input at json.parse (<anonymous>), pay attention to any anonymous functions which involves JSON parsing such as arrow functions or function expression.

If you use IDEs like VS Code or Sublime Text, you’ll also have another way to check the syntax of JSON data: Copy all that JSON data to a completely new file, the default formatter of the software will highlight the syntax error location.

Alternatively, the browser console also supports highlighting common JSON syntax error. You would need to click VMxx:x right next to the exception message.

browser console highlights JSON syntax error

“Unexpected end of JSON input” error due to full localStorage

When the localStorage is full, it might not be able to save the entire JSON string, resulting in an incomplete or invalid JSON string.

When you later try to parse this incomplete JSON string using JSON.parse(), it will throw the “Unexpected end of JSON input” error.

Here’s a simple example to demonstrate this issue:

First, let’s simulate a full localStorage by setting its quota to be unrealisticly small:

// This will set the quota to 1 byte, simulating a full localStorage.
window.localStorage._setQuota(1);Code language: JavaScript (javascript)

Next, let’s create a simple saveSmallData() function to save a small piece of data to localStorage:

function saveSmallData() {
  try {
    const smallData = { key: 'value' };
    const json = JSON.stringify(smallData);
    localStorage.setItem('smallData', json);
  } catch (error) {
    console.log(error.message);
  }
}Code language: JavaScript (javascript)

Now, let’s call the saveSmallData function:

saveSmallData();

Since the localStorage is full (or almost full), it will not be able to save the entire JSON string. The catch block will execute and log the error message to the console.
Finally, let’s try to parse the saved JSON string using JSON.parse():

function parseSmallData() {
  try {
    const json = localStorage.getItem('smallData');
    const smallData = JSON.parse(json);
    console.log(smallData);
  } catch (error) {
    console.log("Error:", error.message);
  }
}

parseSmallData();Code language: JavaScript (javascript)

The parseSmallData function will throw the Unexpected end of JSON input error because the JSON string saved in localStorage is incomplete or invalid due to the storage being full.

To avoid this, you can check the available space in localStorage before saving data in your source code, or handle the error gracefully using a try/catch block as demonstrated in the example above.

Common JSON syntax errors

As most of the time, the error comes from your JSON itself, you should know a few common JSON syntax errors:

The JSON input is not properly formatted (missing closing curly brace):

const json = '{ "key": "value"';Code language: JavaScript (javascript)

The JSON input contains a syntax error (extra characters):

const json = '{ "key": "value" error }';Code language: JavaScript (javascript)

The JSON input has a missing comma:

const json = '{ "key": "value", "key2": "value2" "key3": "value3" }';Code language: JavaScript (javascript)

The JSON input has an extra curly brace:

const json = '{{ "key": "value", "key2": "value2" }';Code language: JavaScript (javascript)

The JSON input has an extra square bracket:

const json = '{ "key": "value", "key2": ["value2", "value3"]] }';Code language: JavaScript (javascript)

The JSON input has a missing quotation mark:

const json = '{ key: "value", "key2": "value2" }';Code language: JavaScript (javascript)

The JSON input has a string that is not properly escaped (missing a backslash before the double quotation mark in the “key3” value):

const json = '{ "key": "value", "key2": "value2", "key3": "She said, "Hello!"" }';Code language: JavaScript (javascript)

Each of these examples will cause a syntax error when attempting to parse the JSON string using JSON.parse().

Error connecting to API: 2001 – Unexpected end of JSON input

This specific Error connecting to API: 2001 - Unexpected end of JSON input is speficic to Wazuh (an open source security platform). The platform relies on Kibana or Elastic as dependencies. It is very likely be due to either Kibana or Elastic running out of space, thus corrupting the data input/output.

First, check your /usr/share/kibana/optimize/wazuh/config/wazuh.yml file to make sure everything is in order. The file structure should look like below:

hosts:
  - default:
     url: https://localhost
     port: 55000
     username: wazuh
     password: wazuh
     run_as: falseCode language: JavaScript (javascript)

Additionally, follow these steps:

Make sure there’s enough available space on your system.
Stop the Kibana service:systemctl stop kibana (run with sudo privileges)
Remove the wazuh-registry.json file by running rm /usr/share/kibana/data/wazuh/config/wazuh-registry.json
Restart the Kibana service to recreate the file:systemctl restart kibana
Clear your browser cache (cookies, local storage, etc.).
Try to access Kibana again.

Conclusion

We hope that the article helps you understand why “Unexpected end of JSON input” happens and how you can correct the input to fix it. If you do a lot of JSON manipulation in JavaScript, you may want to check out our guide on JSON end of file expected, which is another very common one. If you have any suggestions or spot an error in the article, feel free to leave a comment below to let us know.

Источник

How to fix unexpected end of json input: When attempting to parse invalid JSON using the JSON.parse or $.parseJSON functions, the “Unexpected end of JSON input” error occurs.

The issue arises while attempting to parse a value such as an empty array or string. To fix the issue, make sure the JSON is valid before parsing it.

Passing an Empty Array or String to the JSON.parse

index.html:

// Pass an empty array to the JSON.parse() function
// and print the result
console.log(JSON.parse([]));

// Pass an empty string to the JSON.parse() function
// and print the result
console.log(JSON.parse(''));

// Here in both the cases SyntaxError: Unexpected end of JSON
// input occurs

Output:

undefined:1


SyntaxError: Unexpected end of JSON input
at JSON.parse (<anonymous>)
at Object.<anonymous> (/tmp/ER7rLDlJor.js:3:18)
at Module._compile (internal/modules/cjs/loader.js:778:30)
at Object.Module._extensions..js (internal/modules/cjs/loader.js:789:10)
at Module.load (internal/modules/cjs/loader.js:653:32)
at tryModuleLoad (internal/modules/cjs/loader.js:593:12)
at Function.Module._load (internal/modules/cjs/loader.js:585:3)
at Function.Module.runMain (internal/modules/cjs/loader.js:831:12)
at startup (internal/bootstrap/node.js:283:19)
at bootstrapNodeJSCore (internal/bootstrap/node.js:623:3)

Explanation:

Here we got the error after passing an empty array and an empty string  
to the JSON.parse function. 
The same thing would happen if you used the $.parseJSON function.

Passing an Empty Array or String to the $.parseJSON() Function

// Pass an empty string to the $.parseJSON() function
// and print the result
// Here we get an error
console.log($.parseJSON(''));

Explanation:

The error occurs because we are attempting to parse invalid JSON.

The error also arises if you attempt to parse an empty server response or if your server fails to send the relevant CORS headers with the response.

If your server returns an empty response and you attempt to parse it, you will receive an error. You should delete the parsing logic in this situation.

If you’re getting the value from your server, ensure sure the server is setting Content-Type header to application/json.

Json parse unexpected end of input: The “Unexpected end of JSON input” error can be resolved in three ways:

In a try/catch block, wrap your parsing logic.
Ensure that your server returns a valid JSON response
If you expect an empty server response, remove the parsing logic from your code.

NOTE:

You may inspect your server's response by opening your developer tools
 and selecting the Network tab. 
The server's response can be viewed by clicking the Response tab.

Using try/catch Blocks to Avoid Error

index.html:

// Use try-catch blocks to avoid "Unexpected end of JSON input"
// error
try {
  // Pass an empty string to the JSON.parse() function
 // and store it in a variable
  const rslt = JSON.parse('');
  // Print the above result 
  console.log(rslt);
} 
// Handle the "Unexpected end of JSON input" Error inside the 
// catch block
catch (error) {
  // If the error occurs the print some random text and
  // corresponding error
  console.log('Sorry There is an Error!!!!\n', error);
}

Output:

Sorry There is an Error!!!!
SyntaxError: Unexpected end of JSON input
at JSON.parse (<anonymous>)
at Object.<anonymous> (/tmp/ER7rLDlJor.js:6:21)
at Module._compile (internal/modules/cjs/loader.js:778:30)
at Object.Module._extensions..js (internal/modules/cjs/loader.js:789:10)
at Module.load (internal/modules/cjs/loader.js:653:32)
at tryModuleLoad (internal/modules/cjs/loader.js:593:12)
at Function.Module._load (internal/modules/cjs/loader.js:585:3)
at Function.Module.runMain (internal/modules/cjs/loader.js:831:12)
at startup (internal/bootstrap/node.js:283:19)
at bootstrapNodeJSCore (internal/bootstrap/node.js:623:3)

If the JSON.parse() function returns an error as a result of parsing invalid JSON, the error is given as a parameter to the catch function, where it can be handled.

If you know the server’s response does not include valid JSON, you can delete/remove the call to the JSON.parse function.

You can also use an online JSON validator to determine whether a JSON string is valid.

Источник

Method 1: Verify the input string

Method 2: Use try-catch block

Method 3: Stringify the JSON object before parsing

Method 4: Check for special characters in the string

Debug and fix Unexpected end of JSON input

“Unexpected end of JSON input” error due to full localStorage

Common JSON syntax errors

Error connecting to API: 2001 – Unexpected end of JSON input

Conclusion

Passing an Empty Array or String to the JSON.parse

Passing an Empty Array or String to the $.parseJSON() Function

Using try/catch Blocks to Avoid Error

Debug and fix `Unexpected end of JSON input`