Ошибка 1052 sql

I have 2 tables. tbl_names and tbl_section which has both the id field in them. How do I go about selecting the id field, because I always get this error:

1052: Column 'id' in field list is ambiguous

Here’s my query:

SELECT id, name, section
  FROM tbl_names, tbl_section 
 WHERE tbl_names.id = tbl_section.id

I could just select all the fields and avoid the error. But that would be a waste in performance. What should I do?

Shadow's user avatar

Shadow

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asked Jul 10, 2011 at 1:08

Wern Ancheta's user avatar

Wern AnchetaWern Ancheta

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SQL supports qualifying a column by prefixing the reference with either the full table name:

SELECT tbl_names.id, tbl_section.id, name, section
  FROM tbl_names
  JOIN tbl_section ON tbl_section.id = tbl_names.id 

…or a table alias:

SELECT n.id, s.id, n.name, s.section
  FROM tbl_names n
  JOIN tbl_section s ON s.id = n.id 

The table alias is the recommended approach — why type more than you have to?

Why Do These Queries Look Different?

Secondly, my answers use ANSI-92 JOIN syntax (yours is ANSI-89). While they perform the same, ANSI-89 syntax does not support OUTER joins (RIGHT, LEFT, FULL). ANSI-89 syntax should be considered deprecated, there are many on SO who will not vote for ANSI-89 syntax to reinforce that. For more information, see this question.

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answered Jul 10, 2011 at 1:31

OMG Ponies's user avatar

OMG PoniesOMG Ponies

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1

In your SELECT statement you need to preface your id with the table you want to choose it from.

SELECT tbl_names.id, name, section 
FROM tbl_names
INNER JOIN tbl_section 
   ON tbl_names.id = tbl_section.id

OR

SELECT tbl_section.id, name, section 
FROM tbl_names
INNER JOIN tbl_section 
   ON tbl_names.id = tbl_section.id

answered Jul 10, 2011 at 1:11

Taryn's user avatar

2

You would do that by providing a fully qualified name, e.g.:

SELECT tbl_names.id as id, name, section FROM tbl_names, tbl_section WHERE tbl_names.id = tbl_section.id

Which would give you the id of tbl_names

answered Jul 10, 2011 at 1:12

halfdan's user avatar

halfdanhalfdan

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2

Already there are lots of answers to your question, You can do it like this also. You can give your table an alias name and use that in the select query like this:

SELECT a.id, b.id, name, section
FROM tbl_names as a 
LEFT JOIN tbl_section as b ON a.id = b.id;

answered May 25, 2016 at 6:28

Mukesh Joshi's user avatar

Mukesh JoshiMukesh Joshi

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The simplest solution is a join with USING instead of ON. That way, the database «knows» that both id columns are actually the same, and won’t nitpick on that:

SELECT id, name, section
  FROM tbl_names
  JOIN tbl_section USING (id)

If id is the only common column name in tbl_names and tbl_section, you can even use a NATURAL JOIN:

SELECT id, name, section
  FROM tbl_names
  NATURAL JOIN tbl_section

See also: https://dev.mysql.com/doc/refman/5.7/en/join.html

answered Jun 15, 2018 at 20:21

vog's user avatar

vogvog

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What you are probably really wanting to do here is use the union operator like this:

(select ID from Logo where AccountID = 1 and Rendered = 'True')
  union
  (select ID from Design where AccountID = 1 and Rendered = 'True')
  order by ID limit 0, 51

Here’s the docs for it https://dev.mysql.com/doc/refman/5.0/en/union.html

answered May 28, 2015 at 20:34

Bryan Legend's user avatar

Bryan LegendBryan Legend

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0

If the format of the id’s in the two table varies then you want to join them, as such you can select to use an id from one-main table, say if you have table_customes and table_orders, and tha id for orders is like «101«,»102«…»110«, just use one for customers

select customers.id, name, amount, date from customers.orders;

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answered Mar 23, 2014 at 6:16

Festole's user avatar

SELECT tbl_names.id, tbl_names.name, tbl_names.section
  FROM tbl_names, tbl_section 
 WHERE tbl_names.id = tbl_section.id

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answered May 22, 2017 at 13:47

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When working with programs that pull data from databases, you may occasionally run across different types of errors. Many of them are fixable, specifically if you are coding your own SQL queries. This article describes the ‘1052 Column in where clause is ambiguous‘ error and how to correct it.

The Error

This type of error occurs when a SQL query is working with more than one table. Our example below is using two tables within an ecommerce program and generates the following error:

Notice: Error: Column ‘firstname’ in where clause is ambiguous
Error No: 1052
SELECT COUNT(*) AS total FROM oc_customer c LEFT JOIN oc_address a ON (c.customer_id = a.customer_id) WHERE CONCAT(firstname, ‘ ‘, lastname) LIKE ‘%john%’

What causes the error

The query gives each table an alias, the oc_customer table gets an alias of c and the oc_address table gets an alias of a. This is used to define which table the column is supposed to come from, such as the section of the query c.customer_id = a.customer_id. This is the same as saying oc_customer.customer_id = oc_address.customer_id. There is another section that has column names but the script fails to identify which table to look into, CONCAT(firstname, ‘ ‘, lastname). Since both the oc_customer and oc_address tables have columns named firstname and lastname, the server does not know which table to work with, and thus throws the error.

Fixing the error

To fix this, simply add the tablename or alias for the table you want to work with. If you are writing the query yourself, this is a bit easier to deal with as you will know which table you meant to use. In our example, we should add the alias for the oc_customer table, c, to the column names. Our code snippet would look like this: CONCAT(c.firstname, ‘ ‘, c.lastname) making the whole query appear as below.

SELECT COUNT(*) AS total FROM oc_customer c LEFT JOIN oc_address a ON (c.customer_id = a.customer_id) WHERE CONCAT(c.firstname, ‘ ‘, c.lastname) LIKE ‘%john%’

If you are working with a developer or a professional level program (open source or purchased) you will need to let them know of the error. They will be able to fix the issue in their next release.

The query will now run correctly as it knows which table to work with on all columns.

Error ‘1052’ Field is ambiguous. I understand the error that is happening, and I’ve looked at several places for the fix and then applied the inner join function in attempt to fix it. It’s still not working, and it gives me the same error.

EventNo is a primary key in the eventrequest table and a foreign key in the Eventplan table. I’m trying to list the event number, event date, and count of the event plans while only including event requests in the result if the event request has more than one related event plan with a work date in December 2013. This is my code.

SELECT EventNo, DateAuth, COUNT(PlanNo)
FROM eventplan INNER JOIN eventrequest ON eventplan.eventNo = Eventrequest.EventNo
WHERE COUNT(PlanNo) > 1 BETWEEN '2013-12-01' AND '2013-12-31';

asked Feb 21, 2016 at 20:23

Konfu Chicken's user avatar

4

Qualify each column in the SELECT/WHERE and join clauses.

So, for example I’ve qualified the EventNo column so that it’s read from the eventplan table in the SELECT clause — it’s ambiguous because it is in both the eventplan and eventrequest tables.

SELECT eventplan.EventNo, DateAuth, COUNT(PlanNo)
FROM eventplan INNER JOIN eventrequest ON eventplan.eventNo = Eventrequest.EventNo
WHERE COUNT(PlanNo) > 1 BETWEEN '2013-12-01' AND '2013-12-31';

You may nave to do the same for DateAuth and PlanNo if they exist in both tables (in this specific query).

It’s good practice to always fully qualify column names — can make the query easier to read. You can always use a table alias too to cut down on typing.

answered Feb 21, 2016 at 21:38

Philᵀᴹ's user avatar

PhilᵀᴹPhilᵀᴹ

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3

Integrity constraint violations are common errors encountered when working with databases in Laravel. One specific error, «Integrity constraint violation: 1052 Column ‘id’ in where clause is ambiguous,» occurs when you have multiple tables with the same column name and you attempt to perform a query that references that column without specifying the table. In this article, we will explore how to fix this error in Laravel, along with relevant code snippets.

Understanding the Error

The error message «Integrity constraint violation: 1052 Column ‘id’ in where clause is ambiguous» is Laravel’s way of indicating that the ‘id’ column in the WHERE clause is ambiguous because it exists in multiple tables within the query. Laravel requires explicit table references to avoid any ambiguity when dealing with multiple tables that have the same column names.

Fixing the Error Integrity constraint violation: 1052 Column ‘id’ in where clause is ambiguous

To fix the «Integrity constraint violation: 1052 Column ‘id’ in where clause is ambiguous» error, you need to modify your queries and provide explicit table references for the ‘id’ column. Here are two common scenarios and their corresponding solutions:

Scenario 1: Joining Multiple Tables If you’re joining multiple tables and the ‘id’ column exists in more than one table, you should explicitly specify the table name when referencing the ‘id’ column in your WHERE clause. Consider the following code snippet:

$users = DB::table('users')
            ->join('orders', 'users.id', '=', 'orders.user_id')
            ->where('id', '=', 1)
            ->get();

In this case, the ‘id’ column is ambiguous because it exists in both the ‘users’ and ‘orders’ tables. To resolve the ambiguity, you should modify the WHERE clause to explicitly reference the table, as shown below:

$users = DB::table('users')
            ->join('orders', 'users.id', '=', 'orders.user_id')
            ->where('users.id', '=', 1)
            ->get();

By prefixing the ‘id’ column with the table name ‘users’, you eliminate the ambiguity and fix the error.

Scenario 2: Querying a Specific Table If you’re querying a specific table and the ‘id’ column exists in other tables as well, you need to provide the table name in the WHERE clause. Here’s an example:

$orders = DB::table('orders')
             ->where('id', '=', 1)
             ->get();

In this case, the ‘id’ column is ambiguous because it exists in multiple tables. To resolve this, you should modify the WHERE clause to explicitly specify the table name, as shown below:

$orders = DB::table('orders')
             ->where('orders.id', '=', 1)
             ->get();

By explicitly mentioning 'orders.id' in the WHERE clause, you remove the ambiguity and fix the error.

Conclusion

The «Integrity constraint violation: 1052 Column ‘id’ in where clause is ambiguous» error in Laravel occurs when you have multiple tables with the same column name and fail to provide explicit table references. By modifying your queries to include the table name in the WHERE clause, you can resolve the ambiguity and fix the error. Always remember to double-check your code and ensure you’re referencing the correct table when dealing with similar column names in Laravel.

I keep getting an error when I run both of the following queries that the CUST_NUM is ambiguous. How can I fix this?

SELECT  INV_NUM, CUST_NUM, CUST_LNAME, CUST_FNAME, INV_DATE, INV_AMOUNT
FROM    CH08_INVOICE i 
INNER JOIN CH08_CUSTOMER c1 ON (i.CUST_NUM = c1.CUST_NUM)
WHERE   CUST_BALANCE>=1000;


SELECT CUST_LNAME, CUST_FNAME 
FROM CH08_CUSTOMER c1 JOIN CH08_CUSTOMER_2 c2
ON (c1.CUST_LNAME = c2.CUST_LNAME AND c1.CUST_FNAME = c2.CUST_FNAME);

Philip Olson's user avatar

Philip Olson

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asked Oct 7, 2015 at 3:19

Abby Schukei's user avatar

1

SELECT i.INV_NUM, i.CUST_NUM, i.CUST_LNAME, i.CUST_FNAME, i.INV_DATE, i.INV_AMOUNT FROM CH08_INVOICE i INNER JOIN CH08_CUSTOMER c1 ON (i.CUST_NUM = c1.CUST_NUM) WHERE i.CUST_BALANCE>=1000;

SELECT c1.CUST_LNAME, c1CUST_FNAME FROM CH08_CUSTOMER c1 JOIN CH08_CUSTOMER_2 c2 ON (c1.CUST_LNAME = c2.CUST_LNAME AND c1.CUST_FNAME = c2.CUST_FNAME);

Please check this query

answered Oct 7, 2015 at 3:24

makdu's user avatar

makdumakdu

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Ambiguous column means the database don’t know which table it must use the column.

Try using

SELECT  INV_NUM, i.CUST_NUM ...

or

SELECT  INV_NUM, c1.CUST_NUM ...

for explicity defining the table.

answered Oct 7, 2015 at 3:25

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Vini.g.ferVini.g.fer

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