When I try to execute the code
BeautifulSoup(html, ...)
it gives the error message
TypeError: object of type ‘Response’ has no len()
I tried passing the actual HTML as a parameter, but it still doesn’t work.
import requests
url = 'http://vineoftheday.com/?order_by=rating'
response = requests.get(url)
html = response.content
soup = BeautifulSoup(html, "html.parser")
Gino Mempin
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asked Apr 19, 2016 at 5:16
2
You are getting response.content. But it return response body as bytes (docs). But you should pass str to BeautifulSoup constructor (docs). So you need to use the response.text instead of getting content.
answered Apr 19, 2016 at 5:25
0
Try to pass the HTML text directly
soup = BeautifulSoup(html.text)
answered Apr 19, 2016 at 5:21
JorgeJorge
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html.parser is used to ignore the warnings in the page:
soup = BeautifulSoup(html.text, "html.parser")
Tomer Shetah
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answered Jan 10, 2021 at 12:23
If you’re using requests.get('https://example.com') to get the HTML, you should use requests.get('https://example.com').text.
Artjom B.
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answered Oct 18, 2018 at 19:06
Moshe GMoshe G
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you are getting only response code in ‘response’
and always use browser header for security otherwise
you will face many issues
Find header in debugger console network section ‘header’ UserAgent
Try
import requests
from bs4 import BeautifulSoup
from fake_useragent import UserAgent
url = 'http://www.google.com'
headers = {'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_6)
AppleWebKit/537.36 (KHTML, like Gecko) Chrome/71.0.3578.98 Safari/537.36'}
response = requests.get(quote_page, headers=headers).text
soup = BeautifulSoup(response, 'html.parser')
print(soup.prettify())
answered Jan 6, 2019 at 9:21
AtulAtul
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from bs4 import BeautifulSoup
import requests
url = 'your_url'
response = requests.get(url)
html = response.content
soup = BeautifulSoup(html, "html.parser")
print(soup)
answered Dec 14, 2022 at 10:02
bizimundabizimunda
8292 gold badges9 silver badges26 bronze badges
It worked for me:
soup = BeautifulSoup(requests.get("your_url").text)
Now, this code below is better (with lxml parser):
import requests
from bs4 import BeautifulSoup
soup = BeautifulSoup(requests.get("your_url").text, 'lxml')
answered Apr 9, 2019 at 5:08
you should use .text to get content of response
import requests
url = 'http://www ... '
response = requests.get(url)
print(response.text)
or use with soap
import requests
from bs4 import BeautifulSoup
url = 'http://www ... '
response = requests.get(url)
msg = response.text
print(BeautifulSoup(msg,'html.parser'))
answered Jul 12, 2020 at 21:24
mamalmamal
1,80120 silver badges14 bronze badges
import requests
from urllib.request import urlopen
from bs4 import BeautifulSoup
import re
url = "https://fortnitetracker.com/profile/all/DakshRungta123"
html = requests.get(url)
soup = BeautifulSoup(html)
title = soup.text
print(title.text)
ush189
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answered Jul 29, 2020 at 14:10
1
import requests
url = 'http://vineoftheday.com/?order_by=rating'
response = requests.get(url)
html = response.content
soup = BeautifulSoup(html.text, "html.parser")
answered Jun 17, 2022 at 11:58
3
When I try to execute the code
BeautifulSoup(html, ...)
it gives the error message
TypeError: object of type ‘Response’ has no len()
I tried passing the actual HTML as a parameter, but it still doesn’t work.
import requests
url = 'http://vineoftheday.com/?order_by=rating'
response = requests.get(url)
html = response.content
soup = BeautifulSoup(html, "html.parser")
Gino Mempin
25.6k29 gold badges98 silver badges138 bronze badges
asked Apr 19, 2016 at 5:16
2
You are getting response.content. But it return response body as bytes (docs). But you should pass str to BeautifulSoup constructor (docs). So you need to use the response.text instead of getting content.
answered Apr 19, 2016 at 5:25
0
Try to pass the HTML text directly
soup = BeautifulSoup(html.text)
answered Apr 19, 2016 at 5:21
JorgeJorge
1,1369 silver badges15 bronze badges
html.parser is used to ignore the warnings in the page:
soup = BeautifulSoup(html.text, "html.parser")
Tomer Shetah
8,4237 gold badges27 silver badges35 bronze badges
answered Jan 10, 2021 at 12:23
If you’re using requests.get('https://example.com') to get the HTML, you should use requests.get('https://example.com').text.
Artjom B.
61.2k24 gold badges125 silver badges222 bronze badges
answered Oct 18, 2018 at 19:06
Moshe GMoshe G
5161 gold badge4 silver badges13 bronze badges
you are getting only response code in ‘response’
and always use browser header for security otherwise
you will face many issues
Find header in debugger console network section ‘header’ UserAgent
Try
import requests
from bs4 import BeautifulSoup
from fake_useragent import UserAgent
url = 'http://www.google.com'
headers = {'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_6)
AppleWebKit/537.36 (KHTML, like Gecko) Chrome/71.0.3578.98 Safari/537.36'}
response = requests.get(quote_page, headers=headers).text
soup = BeautifulSoup(response, 'html.parser')
print(soup.prettify())
answered Jan 6, 2019 at 9:21
AtulAtul
1,48712 silver badges9 bronze badges
from bs4 import BeautifulSoup
import requests
url = 'your_url'
response = requests.get(url)
html = response.content
soup = BeautifulSoup(html, "html.parser")
print(soup)
answered Dec 14, 2022 at 10:02
bizimundabizimunda
8292 gold badges9 silver badges26 bronze badges
It worked for me:
soup = BeautifulSoup(requests.get("your_url").text)
Now, this code below is better (with lxml parser):
import requests
from bs4 import BeautifulSoup
soup = BeautifulSoup(requests.get("your_url").text, 'lxml')
answered Apr 9, 2019 at 5:08
you should use .text to get content of response
import requests
url = 'http://www ... '
response = requests.get(url)
print(response.text)
or use with soap
import requests
from bs4 import BeautifulSoup
url = 'http://www ... '
response = requests.get(url)
msg = response.text
print(BeautifulSoup(msg,'html.parser'))
answered Jul 12, 2020 at 21:24
mamalmamal
1,80120 silver badges14 bronze badges
import requests
from urllib.request import urlopen
from bs4 import BeautifulSoup
import re
url = "https://fortnitetracker.com/profile/all/DakshRungta123"
html = requests.get(url)
soup = BeautifulSoup(html)
title = soup.text
print(title.text)
ush189
1,3426 gold badges22 silver badges30 bronze badges
answered Jul 29, 2020 at 14:10
1
import requests
url = 'http://vineoftheday.com/?order_by=rating'
response = requests.get(url)
html = response.content
soup = BeautifulSoup(html.text, "html.parser")
answered Jun 17, 2022 at 11:58
3
This error occurs when you try to parse HTML code using the BeautifulSoup constructor but pass a response object instead of the response’s content.
You can solve this error by accessing the Response object’s content using dot notation.
For example,
import requests from bs4 import BeautifulSoup URL = "https://datahub.io/awesome/football" page = requests.get(URL) soup = BeautifulSoup(page.content, "html.parser") print(soup)
This tutorial will go through the error and how to solve it with code examples.
Table of contents
- TypeError: object of type ‘Response’ has no len()
- Example
- Solution
- Summary
TypeError: object of type ‘Response’ has no len()
We raise a Python TypeError when attempting to perform an illegal operation for a specific type. In this case, the type is Response.
The part ‘has no len()‘ tells us the map object does not have a length, and therefore len() is an illegal operation for the Response object.
Retrieving the length of an object is only suitable for iterable objects, like a list or a string.
The len() method implicitly calls the dunder method __len__() , which returns a positive integer representing the length of the object on which it is called.
All iterable objects have __len__ as an attribute.
Let’s check if __len__ is in the list of attributes for the Response object.
import requests
from bs4 import BeautifulSoup
URL = "https://datahub.io/awesome/football"
page = requests.get(URL)
print(type(page))
print('__len__' in dir(page))
<class 'requests.models.Response'> False
We can see that __len__ is not present in the attributes of the Response object.
We can retrieve the content from the response object using dot notation. Dot notation requires putting a dot after the object followed by the attribute we want to access. response.content returns the content of the response in bytes. In Python, bytes is an iterable sequence with a length.
Let’s verify that response.content has __len__ in its list of attributes.
import requests
from bs4 import BeautifulSoup
URL = "https://datahub.io/awesome/football"
page = requests.get(URL)
content = page.content
print(type(content))
print('__len__' in dir(content))
<class 'bytes'> True
We can see that __len__ is present in the attributes of the bytes object.
Example
Let’s look at an example of trying to parse HTML code using BeautifulSoup and Requests. First, we will import the requests module and BeautifulSoup.
import requests from bs4 import BeautifulSoup
Next, we will make a GET request to a web page and save the response as a response object.
URL = "https://datahub.io/awesome/air-pollution" page = requests.get(URL)
Then we can parse the HTML code using the BeautifulSoup constructor. The first argument of the BeautifulSoup constructor is the response object from the GET request, and the second is the appropriate parser for the HTML content.
soup = BeautifulSoup(page, "html.parser")
Let’s run the code to see the result:
TypeError: object of type 'Response' has no len()
The error occurs because the BeautifulSoup constructor requires the response content, not the entire response.
Solution
We can solve the error by retrieving the response content using .content after the response object name.
It is preferable to use .content instead of .text as Requests guesses the text encoding for the response based on the HTTP headers.
Let’s look at the revised code:
import requests from bs4 import BeautifulSoup URL = "https://datahub.io/awesome/air-pollution" page = requests.get(URL) soup = BeautifulSoup(page.content, "html.parser") print(soup)
Let’s run the code to get the result:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8"/>
<title>
Air Pollution Data - Awesome Datasets
- DataHub - Frictionless Data
</title>
....
We successfully parsed the HTML content using the BeautifulSoup constructor.
We can also use .text, for example:
import requests from bs4 import BeautifulSoup URL = "https://datahub.io/awesome/air-pollution" page = requests.get(URL) soup = BeautifulSoup(page.text, "html.parser") print(soup)
Summary
Congratulations on reading to the end of this tutorial!
For further reading on the has no len() TypeErrors, go to the article:
- How to Solve Python TypeError: object of type ‘zip’ has no len()
- How to Solve Python TypeError: object of type ‘builtin_function_or_method’ has no len()
- How to Solve Python TypeError: object of type ‘generator’ has no len()
To learn more about Python for data science and machine learning, go to the online courses page on Python, which provides the best, easy-to-use online courses.
Object of type ‘Response’ has no len() – это распространенная ошибка, с которой могут столкнуться разработчики при работе с HTTP-запросами и ответами в Python. В данной статье мы рассмотрим, что означает эта ошибка, как ее можно исправить и как избежать ее возникновения.
HTTP-запросы и ответы — неотъемлемая часть многих веб-приложений и сервисов, поэтому возможность обрабатывать их в программе на Python является важным навыком для разработчика. Библиотека `requests` предоставляет удобные и мощные инструменты для работы с HTTP-запросами и ответами.
Часто разработчики используют эту библиотеку для отправки HTTP-запросов и получения ответов от внешних сервисов или API. Один из наиболее часто используемых методов в `requests` — это метод `get()`, который выполняет GET-запросы к указанному URL и возвращает объект `Response`.
Пример кода, демонстрирующий отправку GET-запроса с использованием `requests`:
import requests
response = requests.get('https://example.com/api/data')
print(response)
Когда мы выполняем этот код, мы получаем объект `Response`. Однако, если попытаться получить длину объекта `Response` с помощью функции `len()`, то возникнет ошибка `’object of type ‘Response’ has no len()’`.
Почему это происходит? Объект `Response` является итерируемым, но не имеет определенной длины. Функция `len()` в Python используется для получения длины объекта, и в случае с объектом `Response` это некорректная операция.
Вместо использования `len()` для определения длины объекта `Response`, мы можем использовать атрибут `.content` для получения содержимого ответа в виде байтов и затем использовать функцию `len()` для определения длины этого содержимого:
import requests
response = requests.get('https://example.com/api/data')
content = response.content
print(len(content))
В этом примере мы сначала получаем содержимое ответа в виде байтов с помощью атрибута `.content`, а затем используем функцию `len()` для определения длины содержимого. Таким образом, мы можем избежать ошибки `’object of type ‘Response’ has no len()’`.
Однако, в некоторых случаях нам может не требоваться знать точную длину содержимого ответа, а только проверить, что запрос успешно завершился. Для таких ситуаций более удобно использовать атрибут `.status_code`, который содержит код состояния HTTP-ответа.
import requests
response = requests.get('https://example.com/api/data')
if response.status_code == 200:
print('Запрос успешно завершен')
else:
print('Произошла ошибка')
В этом примере мы проверяем, что код состояния HTTP-ответа равен 200, что означает успешное выполнение запроса. Если это условие выполняется, мы выводим сообщение «Запрос успешно завершен», в противном случае — «Произошла ошибка».
В заключение, ошибка `’object of type ‘Response’ has no len()’` возникает, когда мы пытаемся получить длину объекта `Response` с помощью функции `len()`. Чтобы избежать этой ошибки, мы можем использовать атрибут `.content` для получения содержимого ответа в виде байтов и затем использовать функцию `len()` для определения длины этого содержимого, если это необходимо.
The code is as follows:
rom bs4 import BeautifulSoup
import requests
url='XXX'
web=requests.get(url)
soup=BeautifulSoup(web,'lxml')
print(soup)On these lines, the error is:
E:\Python\Python35-32\python.exe C:/Users/ty/PycharmProjects/untitled3/src/Reptile.py
Traceback (most recent call last):
File "C:/Users/ty/PycharmProjects/untitled3/src/Reptile.py", line 7, in <module>
soup=BeautifulSoup(web,'lxml')
File "E:\Python\Python35-32\lib\site-packages\beautifulsoup4-4.5.1-py3.5.egg\bs4\__init__.py", line 192, in __init__
TypeError: object of type 'Response' has no len()
Process finished with exit code 1Why??
answer
soup=BeautifulSoup(web,'lxml')There is a mistake in this place. The web here is a response object, which can’t be parsed by using beautiful soup. If you want to parse, the parsing object should be web.content So the correct way to write it is
soup=BeautifulSoup(web.content,'lxml')